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  • A die is thrown, find the probability of the following events : (ii) A number greater than or equal to 3 will appear

3.(ii)   A die is thrown, find the probability of following events:

   (ii) A number greater than or equal to 3 will appear

Answers (1)

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Sample space when a die is thrown, S = {1,2,3,4,5,6}

\therefore Number of possible outcomes n(S) = 6

Let E be the event of getting a number greater than or equal to 3 = {3,4,5,6}

\therefore n(E) = 4

\therefore P(E) = \frac{n(E)}{n(S)}  = \frac{4}{6} = \frac{2}{3} 

= 0.67

Posted by

HARSH KANKARIA

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