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  • A die is thrown once. Find the probability of getting a number lying between 2 and 6

13.(ii)   A die is thrown once. Find the probability of getting  a number lying between 2 and 6

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Possible outcomes when a die is thrown once = {1,2,3,4,5,6}

Number of possible outcomes = 6

(ii) Let F be the event of getting a number lying between 2 and 6

Numbers lying between 2 and 6 on the die are = {3,4,5}

Number of favourable outcomes = 3

\therefore P(F) = \frac{favourable\ outcomes}{total\ outcomes} = \frac{3}{6}

= \frac{1}{2}

Therefore, the probability of getting a number lying between 2 and 6 is \frac{1}{2}

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HARSH KANKARIA

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