Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • A famous relation in physics relates ‘moving mass’ m to the ‘rest mass’ mo of a particle in terms of its speed v and the speed of light, c. (This relation first arose as a consequence of special relativity due to Albert Einstein).

Q 2.15: A famous relation in physics relates ‘moving mass’ m to the ‘rest mass’ m_{o} of a particle in terms of its speed v and the speed of light, c. (This relation first arose as a consequence of special relativity due to Albert Einstein). A boy recalls the relation almost correctly but forgets where to put the constant c. He writes : m = \frac{m_{o}}{(1-v^2)^{1/2}}

Guess where to put the missing c.

Answers (1)

The relation given is m = \frac{m_{o}}{(1-v^2)^{1/2}}

Divide both sides by m_{o};  \therefore L.H.S becomes m / m_{o} which is dimensionless.

Hence, R.H.S must be dimensionless too. (After Dividing by m_{o} !)

\frac{1}{(1-v^2)^{1/2}} can be dimensionless only when v \rightarrow (v/c)

Therefore, the dimensional equation is m = \frac{m_{o}}{(1-(\frac{v}{c})^2)^{1/2}}

Posted by

Safeer PP

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 English Exam Analysis 2025: Paper rated 'easy, straightforward'; section-wise difficulty level
anam-khan

CBSE 12th Board Exam Live: CBSE Class 12 English paper 'easy and balanced'; answer key updates
anam-khan

CBSE Class 12 Maths paper 2025 'moderate but lengthy', questions from PYQ, NCERT

Latest Question