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  • A galvanometer coil has a resistance of 15 ohm ​​​​​​​ and the metre shows full scale deflection for a current of 4 mA. How will you convert the metre into an ammeter of range 0 to 6 A?

28. A galvanometer coil has a resistance of 15 \Omega  and the metre shows full scale deflection for a current of 4 mA. How will you convert the metre into an ammeter of range 0 to 6 A?

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The galvanometer can be converted into an ammeter by connecting an appropriate resistor of resistance R in series with it.

At the full-scale deflection current(I) of 4 mA, the ammeter must measure a current of 6 A.

The resistance of the galvanometer coil is G =  15 \Omega 

Since the resistor and galvanometer coil are connected in parallel the potential difference is the same across them.

IG=(6-I)R

\\R=\frac{IG}{6-I}\\ \\R=\frac{4\times 10^{-3}\times 15}{6-4\times 10^{-3}}\\ R\approx 0.01\Omega

The galvanometer can be converted into an ammeter by connecting a resistor of resistance 0.01\Omega in parallel with it.

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