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12.(iii) A game of chance consists of spinning an arrow which comes to rest pointing at one of the numbers 1, 2, 3, 4, 5, 6, 7, 8 (see Fig. 15.5), and these are equally likely outcomes. What is the probability that it will point at a number greater than 2?

 

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Total possible outcomes = {1,2,3,4,5,6,7,8}

Number of possible outcomes = 8

Let E be the event of pointing at a number greater than 2

Number of favourable outcomes= n({3,4,5,6,7,8}) = 6

\therefore P(E) = \frac{favourable\ outcomes}{total\ outcomes} = \frac{6}{8} = \frac{3}{4}
Therefore, the probability of pointing at a number greater than 2 is \frac{3}{4}

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HARSH KANKARIA

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