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In a given meter bridge, the balance point is found to be at 39.5 cm from the end A, when the resistor S is 12.5 Ω. Determine the resistance of R. Why are the connections between resistors in a Wheatstone or meter bridge made of thick copper strips?

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Balance Point from the end A, l1 = 39.5 cm

Resistance of S = 12.5 Ω

We know, that for a meter bridge, the balance condition is:

\frac{R}S=\frac{100-l_1}{l_1} \Rightarrow R=\frac{100-39.5}{39.5} \times12.5=8.2 \ \Omega

The connections between resistors in a Wheatstone or meter bridge are made of thick copper strips to minimise the resistance of the connection which is not accounted for in the bridge formula.

 

Posted by

HARSH KANKARIA

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