Get Answers to all your Questions

header-bg qa

3.10    (a) In a meter bridge [Fig. 3.27], the balance point is found to be at 39.5 cm from the end A, when the resistor Y is of 12.5 Ω. Determine the resistance of X. Why are the connections between resistors in a Wheatstone or meter bridge made of thick copper strips?

Answers (1)

best_answer

Balance Point from the end A, l1 = 39.5 cm

Resistance of Y = 12.5 Ω

We know, for a meter bridge, balance condition is:

\frac{X}{Y} = \frac{l_1}{l_2} = \frac{l_1}{100 - l_1}

\implies X = \frac{39.5}{100 - 39.5}\times12.5 = 8.2\Omega

The connections between resistors in a Wheatstone or meter bridge made of thick copper strips to minimise the resistance of the connection which is not accounted for in the bridge formula.

 

Posted by

HARSH KANKARIA

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads