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  • A jet airplane travelling at the speed of 500 km h^–1 ejects its products of combustion at the speed of 1500 km h^–1 relative to the jet plane. What is the speed of the latter with respect to an observer on the ground ?

Q 3.5 A jet airplane travelling at the speed of 500 km h-1 ejects its products of combustion at the speed of 1500 km h-1 relative to the jet plane. What is the speed of the latter with respect to an observer on the ground?

Answers (1)

best_answer

Vairplane=500 km h-1

Vprod/airplane=-1500 km h-1 (the negative sign signifies the Velocity of the plane and the velocity of the ejected combustion products relative to the plane  are in opposite directions)

Vprod/airplane=Vprod - Vairplane

Vprod =Vprod/airplane +Vairplane

Vprod=-1500+500=-1000 km h-1 

The speed of the ejected combustion products with respect to an observer on the ground is 1000 km h-1

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