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  • A jet plane is travelling towards west at a speed of 1800 km/ h What is the voltage difference developed between the ends of the wing having a span of 25 m , if the Earth’s magnetic field at the location has a mag.

Q6.10     A jet plane is travelling towards west at a speed of 1800km/h. What is the voltage difference developed between the ends of the wing having a span of 25m , if the Earth’s magnetic field at the location has a  magnitude of 5\times 10^{-4}T and the dip angle is 30^{0}.

Answers (1)

best_answer

Given

Speed of the plane:

v=1800kmh^{-1}=\frac{1800*1000}{60*60}=500m/s

Earth's magnetic field at that location:

B = 5 *10^{-4}T

The angle of dip that is angle made with horizontal by earth magnetic field:

 \delta = 30 ^0

Length of the wings 

l=25m

Now, Since the only the vertical component of the magnetic field will cut the wings of plane perpendicularly, only those will help in inducing emf.

The vertical component of the earth's magnetic field :

B_{vertical}=Bsin\delta =5*10^{-4}sin30=5*10^{-4}*0.5=2.5*10^{-4}

So now, Induce emf :

e=B_{vertical}lv=2.5*10^{-4}*25*500=3.125V

Hence voltage difference developed between the ends of the wing is  3.125V.

Posted by

Pankaj Sanodiya

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