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2.(a) A parallel plate capacitor (Fig. 8.7) made of circular plates each of radius R = 6.0 cm has a capacitance C = 100 pF. The capacitor is connected to a 230 V AC supply with a (angular) frequency of 300 rad s ^{-1}. What is the rms value of the conduction current?

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It is given that the radius of each circular plate,\ R = 6.0 \, \text{cm}, the capacitance,\ C = 100 \, \text{pF} , the capacitor is connected to a supply of \ V = 230 \, \text{V (AC supply)} \,, and the angular frequency, \ \omega = 300 \, \text{rad/s} .

The formula for the RMS value of conduction current is given by -

\ I_{rms} = V \cdot \omega \cdot C \

Substitute the values:

\\ I_{rms} = 230 \cdot 300 \cdot 100 \cdot 10^{-12} \ \\I_{rms} = 6.9 \cdot 10^{-6} \, \text{A} = 6.9 \, \mu\text{A} \

Thus, the RMS value of the conduction current is \( 6.9 \, \mu\text{A} \).

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