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Q. 8. A random variable $X$ has the following probability distribution:
i) $k$
Answers (1)
The sum of probabilities of the probability distribution of the random variables is 1 .
$\therefore 0+k+2 k+2 k+3 k+k^2+2 k^2+7 k^2+k=1 $
$10 k^2+9 k-1=0$
$(10 k-1)(k+1)=0$
$k= \frac{1}{10}$ and $k=-1$
$k= -1$ is not possible. So, $k=\frac{1}{10}$
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