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Q. 8.     A random variable X has the following probability distribution:

i) k

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The sum of probabilities of the probability distribution of the random variables is 1 .
0+k+2k+2k+3k+k2+2k2+7k2+k=1
10k2+9k1=0
(10k1)(k+1)=0
k=110 and k=1
k=1 is not possible. So, k=110

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seema garhwal

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