Q. 8. A random variable X has the following probability distribution:
i) k
The sum of probabilities of the probability distribution of the random variables is 1 . ∴0+k+2k+2k+3k+k2+2k2+7k2+k=1 10k2+9k−1=0 (10k−1)(k+1)=0 k=110 and k=−1 k=−1 is not possible. So, k=110
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