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Q. 8.     A random variable X has the following probability distribution:

            

            (i)  k

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Sum of probabilities of probability distribution of random variable is 1.

\therefore \, \, \, \, 0+k+2k+2k+3k+k^{2}+2k^{2}+7k^{2}+k=1

           10k^{2}+9k-1=0

         (10k-1)(k+1)=0

k=\frac{1}{10}\, \, and\, \, k=-1

 

Posted by

seema garhwal

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