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Q 9.16 A small pin fixed on a table top is viewed from above from a distance of 50cm. By what distance would the pin appear to be raised if it is viewed from the same point through a 15cm thick glass slab held parallel to the table? Refractive index of glass = 1.5. Does the answer depend on the location of the slab?

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As we know,

Refractive index =

 \frac{actualdepth}{apparentdepth}

Here actual depth = 15cm 

let apparent depth be d' 

And refractive index of the glass = 1.5 

now putting these values, we get,

1.5 = \frac{15}{d'}

d' =10

the change in the apparent depth = 15 - 10 = 5 cm.

as long as we are not taking slab away from the line of sight of the pin, the apparent depth does not depend on the location of the slab.

Posted by

Pankaj Sanodiya

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