Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • A solution containing 30 g of non volatile solute exactly in 90 g of water has a vapour pressure of 2.8 kPa at 298 K. Further,(ii) vapour pressure of water at 298 K

2.19    A solution containing 30\; g of non-volatile solute exactly in 90\; g of water has a vapour pressure of  2.8\; kPa at 298 \; K Further, 18 \; g of water is then added to the solution and the new vapour pressure becomes 2.9 \; kPa at 298 \; K. Calculate

               (ii) vapour pressure of water at 298 K.

Answers (1)

best_answer

In the previous part we have calculated the value of molar mass the Raoul's law equation.

We had :-

                             \frac{p_w^{\circ} }{2.8} = \frac{5M+30}{5M}

Putting M = 23 u in the above equation we get, 

                            \frac{p_w^{\circ} }{2.8} = \frac{5(23)+30}{5(23) } =\frac{145}{115}

or                         p_w^{\circ} =3.53

Thus vapour pressure of water = 3.53 kPa.

Posted by

Devendra Khairwa

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Class 12 Maths paper 2025 'moderate but lengthy', questions from PYQ, NCERT
anam-khan

CBSE Board Exam 2025 Live: Class 12 mathematics paper 'moderate but lengthy'; memory-based questions
anam-khan

CBSE Class 12 Chemistry Exam Analysis 2025: Paper 'moderately difficult' but well balanced

Latest Question