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A solution of \text {KMnO}_{4} on reduction yields either colourless solution or a brown precipitate or a green solution depending on the pH of the solution. What different stages of the reduction do these represent and how are they carried out?

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The oxidising nature of \text {KMnO}_{4} depends on the pH of the solution. They change to colourless manganous ion in acidic medium.

\text {MnO}_{4}^{-}+\text {8H}^{+}+\text {5e}^{-}\rightarrow \text {Mn}^{2+}+\text {4H}_{2}\text {O}

An alkaline solution will turn green because of the formation of manganate

\text {MnO}_{4}^{-}+\text {e}^{-}\rightarrow \text {MnO}_{4}^{2-}

In a neutral solution they will leave a brown precipitate, Manganese Oxide

\text {MnO}_{4}^{-}+\text {2H}_{2}\text {O}+\text {3e}^{-}\rightarrow \text {MnO}_{2}+\text {4OH}^{-}

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