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  • A stone dropped from the top of a tower of height 300 m splashes into the water of a pond near the base of the tower. When is the splash heard at the top given that the speed of sound in air is 340 m s^-1 ? (g = 9.8 m s^-2)

Q.15.2 A stone dropped from the top of a tower of height 300\; m splashes into the water of a pond near the base of the tower. When is the splash heard at the top given that the speed of sound in air is 340 \; m \; s^{-1} ?  (g = 9.8\; m\; s^{-2})

Answers (1)

best_answer

Time taken by the stone to the pond can be calculated using the second equation of motion

s = 300 m

u = 0

a = 9.8 m s-2

\\s=ut_{1}+\frac{1}{2}at_{1}^{2}\\ 300=4.9t_{1}^{2}\\ t_{1}=7.82\ s

Time taken by the wave to propagate from the pond to the top of the tower is

\\t_{2}=\frac{300}{340}\\ t_{2}=0.88\ s

t1 + t2 = 8.7 s

The splash is heard at the top of the tower after a time of 8.7 seconds.

Posted by

Sayak

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