Go To Your Study Dashboard

Get Answers to all your Questions

header-bg

Q5.26 A stone of mass m tied to the end of a string revolves in a vertical circle of radius R. The net forces at the lowest and highest points of the circle directed vertically downwards are : [Choose the correct alternative]

                Lowest Point                              Highest Point

  (a)     $mg - T_1$                                          $mg + T_2$

(b)     $mg + T_1$                                          $mg - T_2$

(c)     $mg + T_1 - (mv_1^2))/R$           $mg - T_2 + (mv_1^2))/R$

(d)     $mg - T_1 - (mv_1^2))/R$            $mg + T_2 + (mv_1^2))/R$

$T_1$ and $v_1$ denote the tension and speed at the lowest point. $T_2$ and $v_2$ denote corresponding values at the highest point.

Answers (1)

best_answer

The FBD of stone at the lowest point is shown below :

Laws of motion, 20275

Using Newton's law of motion,

$T\ -\ mg\ =\ \frac{mv^2}{r}$

The FBD of stone at the highest point is given below :

Laws of motion, 20275 (2)

Using Newton's law of motion we have :

$T\ +\ mg\ =\ \frac{mv^2}{r}$

Thus option (a) is correct.

Posted by

Devendra Khairwa

View full answer

Crack CUET with india's "Best Teachers"

HD Video Lectures
Unlimited Mock Tests
Faculty Support

cuet_ads

Similar Questions

Trending Articles/News

anam-khan

CBSE Date Sheet 2025 (Out) Live: Class 10, 12 board exam time table at cbse.gov.in; syllabus, sample papers

anam-khan

CBSE Class 12 board exam date sheet 2025 out; exams from February 15 to April 4

anam-khan

When will CBSE Board exam 2025 date sheet be released for Class 10, 12?

Latest Question