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  • A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that OQ = 12 cm. Length PQ is : (A) 12 cm (B) 13 cm (C) 8.5 cm (D) 119 cm.

3.   A tangent PQ at a point P of a circle of radius 5 cm meets a line through the centre O at a point Q so that OQ = 12 cm. Length PQ is :

       (A) 12 cm

       (B) 13 cm

       (C) 8.5 cm

       (D) \sqrt { 119} cm.

Answers (1)

best_answer

The correct option is (d) = \sqrt { 119} cm


It is given that the radius of the circle is 5 cm. OQ = 12 cm
According to question,
We know that \angle QPO=90^0
So, triangle OPQ is a right angle triangle. By using pythagoras theorem, 
PQ =\sqrt{OQ^2-OP^2}=\sqrt{144-25}
                                                =\sqrt{119} cm

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manish

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