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Q. 4. A verandah of width $2.25$ m is constructed all along outside a room which is $5.5$ m long and $4$ m wide. Find:

(i) the area of the verandah.

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It is given that the room is 5.5 m long and 4 m wide.
It is clear that it is rectangular shaped with length $=5.5 \mathrm{~m}$ and breadth $=4 \mathrm{~m}$
We know that the area of the rectangle is $=$ length $\times$ breadth
$\Rightarrow$ length $\times$ breadth $=5.5 \times 4=22 \mathrm{~m}^2$-------(i)
Now, when verandah of width $2.25$ m is constructed all along outside the room then the length and breadth of the room  is

The area of the room after the verandah of width $2.25$ m is constructed
$\Rightarrow$ length $\times$ breadth $=10 \times 8.5=85 \mathrm{~m}^2$-------(ii)
Area of verandah is (ii) - (i)$\Rightarrow 85-22=63 m^2$
Therefore, the area of the verandah is $63 \mathrm{~m}^2$.

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Riya

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