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  • A vessel of 120 mL capacity contains a certain amount of gas at 35 ^o C and 1 point 2 bar pressure The gas is transferred to another vessel of volume 180 mL at 35 ^o C What would be its pressure

5.2     A vessel of 120 \; mL capacity contains a certain amount of gas at 35^{o}C and 1.2 bar pressure. The gas is transferred to another vessel of volume 180 \; mL at 35^{o}C. What would be its pressure?

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Given volume of air to be transferred from the capacity of 120 \; mL vessel at 1.2\ bar pressure to 180 \; mL vessel at 35^{o}C

So, as the temperature remains constant at 35^{o}C.

We have Boyle's law where, P_{1}V_{1} = P_{2}V_{2}

To calculate the final pressure P_{2}.

We have,

P_{1}V_{1} = P_{2}V_{2}

P_{2} = \frac{P_{1}V_{1}}{V_{2}}

= \frac{1.2\times 120}{180} bar = 0.8\ bar

Therefore, the pressure required is 0.8\ bar.

Posted by

Divya Prakash Singh

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