1. ABC is a triangle. Locate a point in the interior of which is equidistant from all the vertices of .
We know that the circumcenter of a triangle is equidistant from all the vertices. Also, the circumcenter is the point of intersection of the perpendicular bisectors of the sides of a triangle.
Thus, draw perpendicular bisectors on each side of the triangle ABC. And let them meet at a point, say O.
Hence, O is the required point, which is equidistant from all the vertices.