Q: 7 ABCD is a rhombus. Show that diagonal AC bisects as well as
and diagonal BD bisects
as well as
.
In ADC,
AD = CD (ABCD is a rhombus)
3=
1.................1(angles opposite to equal sides are equal )
3=
2.................2 (alternate angles)
From 1 and 2, we have
1=
2.................3
and 1=
4.................4 (alternate angles)
From 1 and 4, we get
3=
4.................5
Hence, from 3 and 5, diagonal AC bisects angles A as well as angle C.
In ADB,
AD = AB (ABCD is a rhombus)
5=
7.................6(angles opposite to equal sides are equal )
7=
6.................7 (alternate angles)
From 6 and 7, we have
5=
6.................8
and 5=
8.................9(alternate angles)
From 6 and 9, we get
7=
8.................10
Hence, from 8 and 10, diagonal BD bisects angles B as well as angle D.