Q: 7 ABCD is a rhombus. Show that diagonal AC bisects as well as and diagonal BD bisects as well as .
In ADC,
AD = CD (ABCD is a rhombus)
3=1.................1(angles opposite to equal sides are equal )
3=2.................2 (alternate angles)
From 1 and 2, we have
1=2.................3
and 1=4.................4 (alternate angles)
From 1 and 4, we get
3=4.................5
Hence, from 3 and 5, diagonal AC bisects angles A as well as angle C.
In ADB,
AD = AB (ABCD is a rhombus)
5=7.................6(angles opposite to equal sides are equal )
7=6.................7 (alternate angles)
From 6 and 7, we have
5=6.................8
and 5=8.................9(alternate angles)
From 6 and 9, we get
7=8.................10
Hence, from 8 and 10, diagonal BD bisects angles B as well as angle D.