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  • According to Arrhenius equation rate constant k is equal to A \; e-E /RT a. Which of the following options represents the graph of ln k vs 1/T.

According to Arrhenius equation rate constant k is equal to A \; e^{-E_{a} /RT}. Which of the following options represents the graph of ln k vs \frac{1}{T}?

Answers (1)

The answer is the option (i) According to Arrhenius's equation:

k=Ae^{-\frac{E_{a}}{RT}}

ln (k)=ln\left ( Ae^{-\frac{E_{a}}{RT}} \right )

ln\; k =ln\; A-\frac{E_{a}}{RT}

The Arrhenius equation predicts that a small increase in temperature will result in a significant increase in the rate constant. This is because higher temperatures provide more molecules with enough energy to overcome the activation energy barrier and react.

 

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