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  • AD is an altitude of an isosceles triangle ABC in which AB = AC. Show that (ii) AD bisects ∠ A.

2.(ii) AD is an altitude of an isosceles triangle ABC in which \small AB=AC. Show that

   (ii) AD bisects \small \angle A.

Answers (1)

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In the previous part of the question we have proved that    \Delta ABD\ \cong \ \Delta ACD

Thus by c.p.c.t., we can write :             

 \angle BAD\ =\ \angle CAD

Hence AD  bisects  \angle A .

 

Posted by

Devendra Khairwa

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