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Q. 4.18 An aircraft executes a horizontal loop of radius 1.00\; km with a steady speed of 900\; km/h. Compare its centripetal acceleration with the acceleration due to gravity.

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Convert all the physical quantities in SI units.

                             Speed\ =\ 900\times \frac{5}{18}\ 250\ m/s

So the acceleration is given by :

                                           a\ =\ \frac{v^2}{r}

                                                 =\ \frac{(250)^2}{1000}

                                                 =\ 62.5\ m/s^2

The ratio of centripetal acceleration with gravity gives :

                                                \frac{a}{g}=\ \frac{62.5}{9.8}\ =\ 6.38

Posted by

Devendra Khairwa

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