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  • An electric lamp of 100 omega, a toaster of resistance 50 omega, and a water filter of resistance 500 are connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current

  An electric lamp of 100\: \Omega, a toaster of resistance 50\: \Omega and a water filter of resistance 500\: \Omegaare connected in parallel to a 220 V source. What is the resistance of an electric iron connected to the same source that takes as much current as all three appliances, and what is the current through it?

Answers (1)

best_answer

Given : R_1=100\Omega ,R_2=50\Omega ,R_3=500\Omega

    R=Equivalent  resistance

    \frac{1}{R}=\frac{1}{R_1}+\frac{1}{R_2}+\frac{1}{R_3} 

\Rightarrow \frac{1}{R}=\frac{1}{100}+\frac{1}{50}+\frac{1}{500}

\Rightarrow \frac{1}{R}=\frac{5+10+1}{500}=\frac{16}{500}

\Rightarrow R=\frac{500}{16}=31.25\Omega

By Ohm's law,

                   I=\frac{V}{R}=\frac{220}{31.25}=7.04A

Hence, the resistance of electric iron is 31.25 and current through it is 7.04A.

 

 

 

 

 

Posted by

seema garhwal

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