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Q 12.     An object is placed at a distance of 10 cm from a convex mirror of focal length 15 cm. Find the position and nature of the image.

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Object distance, u = -10 cm

Focal length, f = 15 cm

Let the image distance be v

As per the mirror formula

\\\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\\ \frac{1}{15}=\frac{1}{v}+\frac{1}{-10}\\ v=6\ cm

\\Magnification=-\frac{v}{u}\\ =-\frac{6}{-30}\\ =0.2

The image formed is virtual, erect, diminished and is formed 6 cm behind of the mirror.

 

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