Browse by Stream
QnA
Home
QnA
Go To Your Study Dashboard

Get Answers to all your Questions

header-bg qa
  • Home
  • NCERT
  • An object of mass 1 kg travelling in a straight line with a velocity of 10 m s^–1 collides with, and sticks to, a stationary wooden block of mass 5 kg. Then they both move off together in the same straight line. Calculate the total

Q 15.     An object of mass 1 kg travelling in a straight line with a velocity of 10 m s-1 collides with, and sticks to, a stationary wooden block of mass 5 kg. Then they both move off together in the same straight line. Calculate the total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.

Answers (1)

best_answer

For calculating the velocity of the combined mass we need to use the law of conservation of momentum.

                                                              m_1u_1\ +\ m_2u_2\ =\ (m_1\ +\ m_2)v

or                                                         1\times 10\ +\ 5\times 0\ =\ (1\ +\ 5)v

or                                                                                        v\ =\ \frac{10}{6}

or                                                                                        v\ =\ 1.66\ m/s

Now, the momentum before the collision is :

                                                   p_i\ =\ m_1u_1\ +\ m_2u_2

or                                                       =\ 1\times 10\ +\ 5\times 0\ =\ 10\ Kg\ m/s

By momentum conservation, final momentum is also    10\ Kg\ m/s. 

Posted by

Sanket Gandhi

View full answer

Similar Questions

Trending Articles/News

anam-khan

CBSE Date Sheet 2025 Live: CBSE Class 10, 12 board exam timetable soon at cbse.gov.in; practical dates
anam-khan

CBSE Date Sheet 2025 Live: CBSE to announce Class 10, 12 board exam dates soon at cbse.gov.in; sample paper
anam-khan

CBSE Board Exam 2025: Class 10, 12 practical exam dates out at cbse.gov.in; passing marks

Latest Question