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- #Chemistry
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10.16 Arrange the compounds of each set in order of reactivity towards SN2 displacement:
(i) 2-Bromo-2-methylbutane, 1-Bromopentane, 2-Bromopentane
Answers (1)
(i) Here the deciding factor of the rate of reaction will be a steric hindrance tertiary is more hindered than secondary and secondary is more sterically hindered than primary.
It is clear from the above that the order of hindrance is:-
1-Bromopentane < 2-bromopentane < 2-Bromo-2-methylbutane
So the order of rate of reaction will be:-
2-Bromo-2-methylbutane < 2-Bromopentane < 1-Bromopentane
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