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- #Chemistry Part II Textbook for Class XII
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10.16 Arrange the compounds of each set in order of reactivity towards SN2 displacement:
(ii) 1-Bromo-3-methylbutane, 2-Bromo-2-methylbutane, 2-Bromo-3-methylbutane
Answers (1)
(ii) In this case, also, the order of the rate of reaction will be decided from the steric hindrance factor.
It is clear from the above that the steric hindrance in 2-Bromo-2-methylbutane highest (note that hindrance of the carbon attached to halide ion is seen). So the order of the rate of reaction is:-
2-Bromo-2-methylbutane < 2-Bromo-3-methylbutane < 1-Bromo-3-methylbutane
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