Arrange the following carbanions in order of their decreasing stability.
(i) A > B > C
(ii) B > A > C
(iii) C > B > A
(iv) C > A > B
The answer is the option (ii) B > A > C
Explanation: CH3 group has +I effect, which decreases the stability of carbon anion and in C this effect direct to negatively charged carbon. +I effect is also present in A, but there is more distant from negatively charged carbon, and in B there is no +I effect