9.16 arrange the following
(iii) H–H, D–D and F–F in order of increasing bond dissociation enthalpy
Answer-
increasing order of bond dissociation enthalpy
In F-F high repulsion force is acting so breaking should be easy.
while in case of H-H and D-D, bond pair of D-D is more strongly attracted by the nucleus because of the higher nucleus mass in D2. we know that higher the attraction high is the bond strength.