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  • At a hydroelectric power plant, the water pressure head is at a height of 300 m and the water flow available is 100 m3s–1. If the turbine generator efficiency is 60%, estimate the electric power available from the plant.

Q7.24   At a hydroelectric power plant, the water pressure head is at a height  of 300m and the water flow available is 100m^{3}s^{-1}. If the turbine generator efficiency is 60^{0}/_{0}, estimate the electric power availablefrom the plant (g=9.8ms^{-2}).

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best_answer

Given,

Height of the water pressure head 

h=300m

The volume of the water flow per second

V=100m^3s^{-1}

Turbine generator efficiency

\eta =0.6

Mass of water flowing per second

M=100*10^3=10^5kg

The potential energy stored in the fall for 1 second

P=Mgh=10^5*9.8*300=294*10^6J

Hence input power 

P_{input}=294*10^6J/s

Now as we know,

\eta =\frac{P_{output}}{P_{input}}

P_{output}=\eta *P_{input}=0.6*294*10^6=176.4*10^6W

Hence output power is 176.4 MW.

Posted by

Pankaj Sanodiya

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