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Q 9.22  At what angle should a ray of light be incident on the face of a prism of refracting angle 60^{\circ}so that it just suffers total internal reflection at the other face? The refractive index of the prism material is as follows:

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Let prism be ABC,

as emergent angle e=90^0,

\mu_{glass}sinr_2 = 1sin90 

sinr_2=\frac{1}{1.524} = 0.6562

r_2= 41 ^0 (approx)

Now as we know in the prism 

r_1+r_2=A

Hence, r_1+=A-r_2=60-41=19^0

Now applying Snell's law at surface AB

1sini=\mu _{glass}sinr_1

sini=1.524sin19

sini=0.496

i = 29.75^0

Hence the angle of the incident is 29.75 degrees.

Posted by

Pankaj Sanodiya

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