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  • (b) Determine the balance point of the bridge above if X and Y are interchanged.

In a given meter bridge, the balance point is found to be at 39.5 cm from the end A, when the resistor S is 12.5 Ω. Determine the resistance of R. Why are the connections between resistors in a Wheatstone or meter bridge made of thick copper strips?  Determine the balance point of the bridge above if R and S are interchanged.

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Balance point from end A, l1 = 39.5 cm

Resistance of the resistor S = 12.5 Ω

Condition for the balance bridge is given as,

\frac{R}S=\frac{100-l_1}{l_1} \Rightarrow R=\frac{100-39.5}{39.5} \times12.5=8.2 \ \Omega

Therefore, the resistance of resistor R is 8.2 Ω

If R and S are interchanged.

Then, R = 12.5 Ω , S = 8.2 Ω

We know, that for a meter bridge, the balance condition is:

\frac{R}S= \frac{l_1}{l_2}=\frac{l_1}{100-l_1}

\Rightarrow\frac{12.5}{8.2}=\frac{l_1}{100-l_1} \Rightarrow 1.53 \times(100-l_1)=l_1 \Rightarrow2.53l_1=153

\therefore l_1 =60.5 cm (from \ point\ A) 

Hence, the balance point is 60.5 cm from A.

Posted by

HARSH KANKARIA

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