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  • (b) If the combination is connected to a battery of emf 12 V and negligible internal resistance, obtain the potential drop across each resistor.

3.3 (b) If the combination is connected to a battery of emf 12 V and negligible internal resistance, obtain the potential drop across each resistor.

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Since the resistances are in series, the current through each one of them will be equal to the current through the circuit but voltage/ potential drop will be different.

Total resistance, R = 6 \Omega

Emf, V = 12 V

According to Ohm's law:

V = IR

\implies12 = I x  6

\implies I = 12/6 = 2 A

Now, Using the same relation, voltage through resistors:

1\Omega : V(1) = 2 x 1 = 2V

2\Omega : V(2) = 2 x 2 = 4V

3\Omega : V(3) = 2 x 3 = 6V

(Note: V(1) + V(2) + V(3) = 2 + 4 + 6 = 12 V )

Posted by

HARSH KANKARIA

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