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  • (b) If the combination is connected to a battery of emf 20 V and negligible internal resistance, determine the current through each resistor, and the total current drawn from the battery.

3.4    (b) If the combination is connected to a battery of emf 20 V and negligible internal resistance, determine the current through each resistor, and the total current drawn from the battery.

Answers (2)

best_answer

Since the resistances are in parallel, the voltage across each one of them will be equal.

Emf, V = 20 V

According to Ohm's law:

V = IR \implies I = V/R

Therefore, current across each one of them is:

2\Omega:  I = 20/2 = 10 A

4\Omega:  I = 20/4 = 5 A

5\Omega:  I = 20/5 = 4 A

Posted by

HARSH KANKARIA

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Since the resistances are in parallel, the voltage across each one of them will be equal.

Emf, V=20V

According to Ohm's law:

V=IR implies I=V/R

Therefore, current across each one of them is:

2\Omega: I = 20/2 = 10 A

4\Omega: I = 20/4 = 5 A

5\Omega: I = 20/5 = 4 A

Posted by

Rakesh Konashirasagi

View full answer

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