Based on crystal field theory explain why {Co(III)} forms a paramagnetic octahedral complex with weak field ligands whereas it forms a diamagnetic octahedral complex with strong field ligands.

Name: Based on crystal field theory explain why {Co(III)} forms a paramagnetic octahedral complex with weak field ligands whereas it forms a diamagnetic octahedral complex with strong field ligands.
Uploaded: Thu, 2020-11-26 14:49
Description: Based on crystal field theory explain why {Co(III)} forms a paramagnetic octahedral complex with weak field ligands whereas it forms a diamagnetic octahedral complex with strong field ligands.

#Exemplar Chemistry for Class 12
#Coordination compounds
#Chemistry
#NCERT

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Based on crystal field theory explain why $\text {Co(III)}$ forms a paramagnetic octahedral complex with weak field ligands whereas it forms a diamagnetic octahedral complex with strong field ligands.

Answers (1)

$t^{4}_{2g} e^{2} _{g}$ will be the electronic configuration where it indicates that it has 4 unpaired electrons and is paramagnetic, with a weak ligand $\Delta _{0}<p$ . The configuration will be $t^{6}_{2g} e^{0}_{g}$ with strong field ligand and there will not be any unpaired electrons. Hence it is diamagnetic.

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Based on crystal field theory explain why forms a paramagnetic octahedral complex with weak field ligands whereas it forms a diamagnetic octahedral complex with strong field ligands.

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Based on crystal field theory explain why $\text {Co(III)}$ forms a paramagnetic octahedral complex with weak field ligands whereas it forms a diamagnetic octahedral complex with strong field ligands.