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Bond dissociation enthalpy of E-H \left ( E = element \right ) bonds are given below. Which of the compounds will act as the strongest reducing agent?

Compound

\Delta _{diss} \left ( E-H \right )/kJ\; mol^{-1}

NH_{3}

389

PH_{3}

322

AsH_{3}

297

SbH_{3}

255

(i) NH_{3}

(ii) PH_{3}

(iii) AsH_{3}

(iv) SbH_{3}

Answers (1)

The answer is the option (iv). The bond dissociation enthalpy decreases down the group. SbH_{3} has the least bond enthalpy and thus acts as the strongest reducing agent.

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infoexpert23

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