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By repeated subtraction of odd numbers starting from 1, find whether the following numbers are perfect squares or not? If the number is a perfect square then find its square root.

(iii) 36

Answers (1)

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We have $\sqrt{36}$ . Then

36 - 1 = 35

35 - 3 = 32

32 - 5 = 27

27 - 7 = 20

20 - 9 = 11

11 - 11 = 0 .

We get zero on the 6th step so $\sqrt{36} = 6$

Posted by

Devendra Khairwa

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