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  • (c) Determine the equivalent resistance of networks shown in Fig. 3.31.

3.20 (c) Determine the equivalent resistance of networks shown in Fig.(a)

    

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It can be seen that in every small loop resistor, 1 ohm is in series with another 1Ω resistor and two 2Ω  are also in series and we have 4 loops,

So, the equivalent resistance of one loop is equal to the parallel combination of 2 Ω and 4 Ω.  that is,

Equivalent\ R_{loop}=\frac{2*4}{2+4}=\frac{8}{6}=\frac{4}{3}

Now we have 4 such loops in a series so, 

Total\ Equivalent\ R_{loop}=\frac{4}{3}+\frac{4}{3}+\frac{4}{3}+\frac{4}{3}=\frac{16}{3}

Hence, the equivalent resistance of the circuit is \frac{16}{3}\Omega.

Posted by

Pankaj Sanodiya

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