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  • Calculate the mass of sodium acetate (CH 3 COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol –1 .

1.5  Calculate the mass of sodium acetate (CH3COONa) required to make 500 mL of 0.375 molar aqueous solution. Molar mass of sodium acetate is 82.0245 g mol –1.

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0.375 molar aqueous solution would contain 0.375 moles of CH_{3}COONa dissolved in 1000mL of solvent.

So, we have to calculate for 500mL solution of CH_{3}COONa.

Therefore the number of moles of sodium acetate in 500mL will be:

= \frac{0.375}{1000}\times 500

=0.1875\ mole

Given Molar mass of sodium acetate: 82.0245\ g\ mol^{-1}

So, the required mass of sodium acetate = (82.0245\ g\ mol^{-1})\times (0.1875\ mole)

= 15.38\ grams

Posted by

Divya Prakash Singh

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