Get Answers to all your Questions

header-bg qa

8.24 Calculate the number of unpaired electrons in the following gaseous ions:

(ii)\; Cr^{3+}

Answers (1)

best_answer

The electronic configuration of chromium is Cr = 3d^{5}4s^{1}. The number of unpaired electrons in Cr^{3+} is 3
Cr^{3+}(Z=24) =\left [ Ar \right ] 3d^{3} after losing 3 electrons, Cr has 3 electrons left in the d-orbital.

 

Posted by

manish

View full answer

Crack CUET with india's "Best Teachers"

  • HD Video Lectures
  • Unlimited Mock Tests
  • Faculty Support
cuet_ads