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  • Calculate the pH of the resultant mixtures: c) 10 mL of 0.1M H_2SO_4 + 10 mL of 0.1M KOH

7.66     Calculate the pH of the resultant mixtures:

     c) 10 mL of 0.1M H2SO4 + 10 mL of 0.1M KOH

Answers (1)

best_answer

Given that,

Volume of 0.1 M KOH = 10 mL, and 

Volume of 0.1 M H_2SO_{4} = 10 mL

So, by using the formula of,

M(H^+)=\frac{M_1V_1(acid)-M_2V_2(base)}{V_1+V_2}
By putting the values we get,

\\\Rightarrow \frac{2(0.1\times 10)-0.1\times 10}{10+10}\\ =\frac{1}{20}\\ =5\times 10^{-2}

Hence, pH = -\log[H^+] = -\log(5\times 10^{-2})= 1.30

Posted by

manish

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