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  • Calculate the total number of electrons present in 1.4 g of dinitrogen gas.

5.13     Calculate the total number of electrons present in 1.4 g of dinitrogen gas.

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Dinitrogen N_{2}  has a molar mass = 28g\ mol^{-1}.

Given 1.4g of N_{2} gas.

That means \frac{1.4}{28} = 0.05\ mol

= 0.05\times6.02\times10^{23} = 3.01\times 10^{23} number of molecules.

And as 1 molecule of N_{2} has 14 electrons.

So, 3.01\times 10^{23} molecules of N_{2} has 14\times 3.01\times 1023 = 4.214\times 10^{23} electrons.

Posted by

Divya Prakash Singh

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