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  • Can two numbers have 18 as their HCF and 380 as then LCM Give reasons.

Can two numbers have 18 as their HCF and 380 as then LCM? Give reasons.

Answers (1)

As we know, LCM is a multiple of HCF
\frac{LCM}{HCF}has to be an integer.
If the given statement is true:
380 = 18n where n is any integer.
But there is no such type of n exist as we can say that 380 is not divisible by 18.
  Hence two numbers, with 18 as their HCF and 380 as their LCM, do not exist.

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infoexpert27

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