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  • Check what the result would have been if Sundaram had chosen the numbers shown below. 2. 632

Check what the result would have been if Sundaram had chosen the numbers
shown below.

    Q2. 632

Answers (2)

best_answer

Let choosen number be abc then,

abc = 100a + 10b + c

cab = 100c + 10a + b

bca = 100b + 10c + a

The addition of all the above three, abc + cab + bca = 111(a + b + c) = 37 × 3(a + b + c), which is divisible by 37

here a = 6, b = 3, and c = 2

632+ 263+ 362= 1221= 37*33 i.e. divisible by 37.

Posted by

Pankaj Sanodiya

View full answer

Let chosen number be abc then,

abc = 100a + 10b + c

cab = 100c + 10a + b

bca = 100b + 10c + a

abc + cab + bca = 111(a + b + c) = 37 × 3(a + b + c), which is divisible by 37

here a = 6, b = 3, and c = 2

632+ 263+ 362= 1221= 37*33 i.e. divisible by 37.

Posted by

Pankaj Sanodiya

View full answer

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