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  • Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential difference of 50 V.

Q. 2.     Compute the heat generated while transferring 96000 coulomb of charge in one hour through a potential              difference of 50 V.

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Given : potential  difference = 50 V.

                 Charge = 9600 C

                time = 1 hr=3600 s

I=\frac{charge}{time(seconds)}=\frac{9600}{3600}=\frac{80}{3}A

So,     H=VIt

       \Rightarrow H=50\times \frac{80}{3}\times 3600

      \Rightarrow H=4800000J=4.8\times 10^6J

Posted by

seema garhwal

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