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11.4     Consider the compounds, BCl_{3}  and CCl_{4}. How will they behave with water ? Justify.

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BCl_{3} is a Lewis acid, it is an electron deficient molecules. So, it readily undergoes to hydrolysis. On hydrolysis gives boric acid.

BCl_3+H_{2}O\rightarrow 3HCl+B(OH)_3

CCl_{4} does not undergo hydrolysis because carbon has no vacant orbital, so it cannot accept an electron from the water molecule to form intermediate.
CCl_{4}  + water \rightarrow no reaction

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