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3.12    Consider the reaction:  Cr_{2}O_{7}^{2-}+ 14H^+ + 6e^-\rightarrow 2cr^{3+} + 7H_{2}O
           What is the quantity of electricity in coulombs needed to reduce 1 mol  of Cr_{2}O_{7}^{2-} ?
 

Answers (1)

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It is clear from the given reaction that reduction of 1 mol of Cr2O72- will be 

                                                                     =   6 F                                                            (as 6 electrons are required to balance the reaction;  Charge required = nF)

                                                                    = 6\times96500

                                                                    = 579000\ C

Thus 578922 C charge is required for reduction of 1 mol of Cr2O72- .

Posted by

Devendra Khairwa

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