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  • Construct a triangle with sides 5 cm, 6 cm and 7 cm and then another triangle whose sides are 7 / 5 of the corresponding sides of the first triangle.

3.   Construct a triangle with sides 5 cm, 6 cm and 7 cm and then another triangle whose sides are 7 / 5 of the corresponding sides of the first triangle.

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Steps of construction are:- 

(i) Firstly draw a line segment AB of length 5 cm.

(ii) Now cut an arc of radius 6 cm from point A and an arc of 7 cm from point B.

(iii) Name the point of intersection of arcs to be point C. 

(iv) Now join point AC and BC. Thus \Delta ABC is the required triangle.

(v) Draw a line AD which makes an acute angle with AB and is opposite of vertex C.

(vi) Cut seven equal parts of line AD namely  AA1, AA2, AA3, AA4, AA5, AA6, AA7,.

(vii) Now join A5 to B. Draw a line A7B' parallel to A5B.

(viii) And then draw a line B'C' parallel to BC.

Hence \Delta AB'C' is the required triangle.

                                                                                   

Posted by

Devendra Khairwa

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