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  • Construct an isosceles triangle whose base is 8 cm and altitude 4 cm and then another triangle whose sides are 1 1 by 2 times the corresponding sides of the isosceles triangle.

4.   Construct an isosceles triangle whose base is 8 cm and altitude 4 cm and then another triangle whose sides are 3/ 2 times the corresponding sides of the isosceles triangle.

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Steps of construction:-  

(i) Draw a line segment AB of length 8 cm. 

(ii) Cut arcs taking point A and point B as the centre. Draw the line to intersect on line segment AB. Mark the intersecting point as point D.

(iii) Cut an arc of length 4 cm on the same line which will be the altitude of the triangle.

(iv) Name the point as C. Then \Delta ABC is the isosceles triangle.

(v) Draw a line AX which makes an acute angle with AB and is opposite of vertex C.

(vi) Cut seven equal parts of line AX namely  AA1, AA2, AA3.

(vii) Now join A2 to B. Draw a line A3B' parallel to A2B.

(viii) And then draw a line B'C' parallel to BC.

Hence \Delta AB'C' is the required triangle.

 

Posted by

Devendra Khairwa

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